t^2-13t+50=0

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Solution for t^2-13t+50=0 equation: 



t^2-13t+50=0

a = 1; b = -13; c = +50;
Δ = b2-4ac
Δ = -132-4·1·50
Δ = -31
Delta is less than zero, so there is no solution for the equation

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